Find the matrix represented by (A^5)-(4*A^4)-(7×A^3)+(11×A^2)-A-(10×I) [closed]
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Can any one please explain how to find matrix when it's characteristic polynomial is given
linear-algebra
closed as off-topic by TheSimpliFire, Lord Shark the Unknown, uniquesolution, Math1000, Claude Leibovici Jul 25 at 5:41
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Can any one please explain how to find matrix when it's characteristic polynomial is given
linear-algebra
closed as off-topic by TheSimpliFire, Lord Shark the Unknown, uniquesolution, Math1000, Claude Leibovici Jul 25 at 5:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – TheSimpliFire, uniquesolution, Math1000, Claude Leibovici
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up vote
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up vote
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Can any one please explain how to find matrix when it's characteristic polynomial is given
linear-algebra
Can any one please explain how to find matrix when it's characteristic polynomial is given
linear-algebra
asked Jul 25 at 5:23


bharathi b
62
62
closed as off-topic by TheSimpliFire, Lord Shark the Unknown, uniquesolution, Math1000, Claude Leibovici Jul 25 at 5:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – TheSimpliFire, uniquesolution, Math1000, Claude Leibovici
closed as off-topic by TheSimpliFire, Lord Shark the Unknown, uniquesolution, Math1000, Claude Leibovici Jul 25 at 5:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – TheSimpliFire, uniquesolution, Math1000, Claude Leibovici
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1 Answer
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The characteristic polynomial is in and of itself insufficient to determine the originating matrix. Perhaps the easiest way to see this is to contemplate the fact that in addition to eigenvalues, eigenvectors are also required to specify a matrix, and the characteristic polynomial says very little about eigenvectors.
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
The characteristic polynomial is in and of itself insufficient to determine the originating matrix. Perhaps the easiest way to see this is to contemplate the fact that in addition to eigenvalues, eigenvectors are also required to specify a matrix, and the characteristic polynomial says very little about eigenvectors.
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up vote
1
down vote
The characteristic polynomial is in and of itself insufficient to determine the originating matrix. Perhaps the easiest way to see this is to contemplate the fact that in addition to eigenvalues, eigenvectors are also required to specify a matrix, and the characteristic polynomial says very little about eigenvectors.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
The characteristic polynomial is in and of itself insufficient to determine the originating matrix. Perhaps the easiest way to see this is to contemplate the fact that in addition to eigenvalues, eigenvectors are also required to specify a matrix, and the characteristic polynomial says very little about eigenvectors.
The characteristic polynomial is in and of itself insufficient to determine the originating matrix. Perhaps the easiest way to see this is to contemplate the fact that in addition to eigenvalues, eigenvectors are also required to specify a matrix, and the characteristic polynomial says very little about eigenvectors.
answered Jul 25 at 5:40


Robert Lewis
36.9k22155
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