How to find the measure of the segment in the trapezoid's median being intersected by its diagonals?
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Given the trapezoid $ABCD$ with EF as median, what is the measure of segment $PQ$? $AB = 16$ cm, $DC = 24$ cm and PQ lies on the median $EF$ being cut by diagonals $AC$ and $BD$.
I have been looking for any theorems on trapezoid for me to be able to answer this problem. I am only able to find the measure of segment by mere illustration. Is there any theorems that can help me answer this question?
geometry euclidean-geometry
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up vote
1
down vote
favorite
Given the trapezoid $ABCD$ with EF as median, what is the measure of segment $PQ$? $AB = 16$ cm, $DC = 24$ cm and PQ lies on the median $EF$ being cut by diagonals $AC$ and $BD$.
I have been looking for any theorems on trapezoid for me to be able to answer this problem. I am only able to find the measure of segment by mere illustration. Is there any theorems that can help me answer this question?
geometry euclidean-geometry
A diagram might help as I cannot understand where $P$ and $Q$ are supposed to be
– Henry
Jul 30 at 12:15
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Given the trapezoid $ABCD$ with EF as median, what is the measure of segment $PQ$? $AB = 16$ cm, $DC = 24$ cm and PQ lies on the median $EF$ being cut by diagonals $AC$ and $BD$.
I have been looking for any theorems on trapezoid for me to be able to answer this problem. I am only able to find the measure of segment by mere illustration. Is there any theorems that can help me answer this question?
geometry euclidean-geometry
Given the trapezoid $ABCD$ with EF as median, what is the measure of segment $PQ$? $AB = 16$ cm, $DC = 24$ cm and PQ lies on the median $EF$ being cut by diagonals $AC$ and $BD$.
I have been looking for any theorems on trapezoid for me to be able to answer this problem. I am only able to find the measure of segment by mere illustration. Is there any theorems that can help me answer this question?
geometry euclidean-geometry
edited Jul 30 at 12:10


greedoid
26.1k93473
26.1k93473
asked Jul 30 at 11:33
Samuel John Parreño
206
206
A diagram might help as I cannot understand where $P$ and $Q$ are supposed to be
– Henry
Jul 30 at 12:15
add a comment |Â
A diagram might help as I cannot understand where $P$ and $Q$ are supposed to be
– Henry
Jul 30 at 12:15
A diagram might help as I cannot understand where $P$ and $Q$ are supposed to be
– Henry
Jul 30 at 12:15
A diagram might help as I cannot understand where $P$ and $Q$ are supposed to be
– Henry
Jul 30 at 12:15
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
Say we have points $E-P-Q-F$ on median and $E$ is on $AD$.
Then since $EP$ is median in $ACD$ we have $EP = CD/2$,
and $QF$ is median in $BCD$, so we have $QF = CD/2$.
So $$PQ = EF - EP-QF = AB+CDover 2-CD = AB-CDover 2 = 4$$
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Say we have points $E-P-Q-F$ on median and $E$ is on $AD$.
Then since $EP$ is median in $ACD$ we have $EP = CD/2$,
and $QF$ is median in $BCD$, so we have $QF = CD/2$.
So $$PQ = EF - EP-QF = AB+CDover 2-CD = AB-CDover 2 = 4$$
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
add a comment |Â
up vote
0
down vote
accepted
Say we have points $E-P-Q-F$ on median and $E$ is on $AD$.
Then since $EP$ is median in $ACD$ we have $EP = CD/2$,
and $QF$ is median in $BCD$, so we have $QF = CD/2$.
So $$PQ = EF - EP-QF = AB+CDover 2-CD = AB-CDover 2 = 4$$
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Say we have points $E-P-Q-F$ on median and $E$ is on $AD$.
Then since $EP$ is median in $ACD$ we have $EP = CD/2$,
and $QF$ is median in $BCD$, so we have $QF = CD/2$.
So $$PQ = EF - EP-QF = AB+CDover 2-CD = AB-CDover 2 = 4$$
Say we have points $E-P-Q-F$ on median and $E$ is on $AD$.
Then since $EP$ is median in $ACD$ we have $EP = CD/2$,
and $QF$ is median in $BCD$, so we have $QF = CD/2$.
So $$PQ = EF - EP-QF = AB+CDover 2-CD = AB-CDover 2 = 4$$
answered Jul 30 at 12:09


greedoid
26.1k93473
26.1k93473
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
add a comment |Â
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
Why does EP = CD/2 ?
– Samuel John Parreño
Jul 30 at 12:32
add a comment |Â
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A diagram might help as I cannot understand where $P$ and $Q$ are supposed to be
– Henry
Jul 30 at 12:15