How to rewrite exponential function $e^x+c$ into $ce^x$? [closed]
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Tried to rewrite $e^x+c$ by using exponential properties $e^x.e^c=e^x+c$ but struggle to understand how to get into $ce^x$. Is it always the case that $c=e^c$?
Edit: To put in context, I solved a separable differential equation $fracdydx=y$, I get the solution is $y = e^x+c$. But the solution in the book is written $y=ce^x$.
differential-equations
closed as off-topic by Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus Jul 18 at 1:43
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus
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up vote
-1
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Tried to rewrite $e^x+c$ by using exponential properties $e^x.e^c=e^x+c$ but struggle to understand how to get into $ce^x$. Is it always the case that $c=e^c$?
Edit: To put in context, I solved a separable differential equation $fracdydx=y$, I get the solution is $y = e^x+c$. But the solution in the book is written $y=ce^x$.
differential-equations
closed as off-topic by Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus Jul 18 at 1:43
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus
1
Note that if $C=e^c$ then $e^x+c=e^ccdot e^x=C e^x$.
– Math Lover
Jul 17 at 21:07
1
$e^x+c = e^ce^x$. Now define $C:=e^c$.
– amsmath
Jul 17 at 21:08
1
It would be really helpful if you could provide some additional context. My guess is that this is popping up in an elementary calculus or differential equations class, where the solution to some DE is of the form $mathrme^x+c$, where $c$ is some constant of integration, which ultimately depends on some initial condition. As others have pointed out, $mathrme^c$ is then also a constant depending on the initial condition, so it does no harm to relabel the constants and set $c = mathrme^c$ (where the $c$ on the left is different from the $c$ on the right).
– Xander Henderson
Jul 18 at 0:48
If you are worried about keeping track of the constants, perhaps write $$mathrme^x + C_1 = mathrme^C_1 mathrme^x = C_2 mathrme^x, $$ where both $C_1$ and $C_2$ are constant, subject to the relation $C_2 := mathrme^C_1$.
– Xander Henderson
Jul 18 at 0:49
@XanderHenderson Yes, I'm trying to solve a differential equation $fracdydx=y$. By the way, can you helped me to understand in which situation that we can't relabel $c=e^c$. Thanks for your comment, I've edited my question.
– reckn
Jul 18 at 20:30
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show 1 more comment
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Tried to rewrite $e^x+c$ by using exponential properties $e^x.e^c=e^x+c$ but struggle to understand how to get into $ce^x$. Is it always the case that $c=e^c$?
Edit: To put in context, I solved a separable differential equation $fracdydx=y$, I get the solution is $y = e^x+c$. But the solution in the book is written $y=ce^x$.
differential-equations
Tried to rewrite $e^x+c$ by using exponential properties $e^x.e^c=e^x+c$ but struggle to understand how to get into $ce^x$. Is it always the case that $c=e^c$?
Edit: To put in context, I solved a separable differential equation $fracdydx=y$, I get the solution is $y = e^x+c$. But the solution in the book is written $y=ce^x$.
differential-equations
edited Jul 18 at 20:22
asked Jul 17 at 21:05


reckn
72
72
closed as off-topic by Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus Jul 18 at 1:43
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus
closed as off-topic by Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus Jul 18 at 1:43
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, amWhy, Xander Henderson, Isaac Browne, Leucippus
1
Note that if $C=e^c$ then $e^x+c=e^ccdot e^x=C e^x$.
– Math Lover
Jul 17 at 21:07
1
$e^x+c = e^ce^x$. Now define $C:=e^c$.
– amsmath
Jul 17 at 21:08
1
It would be really helpful if you could provide some additional context. My guess is that this is popping up in an elementary calculus or differential equations class, where the solution to some DE is of the form $mathrme^x+c$, where $c$ is some constant of integration, which ultimately depends on some initial condition. As others have pointed out, $mathrme^c$ is then also a constant depending on the initial condition, so it does no harm to relabel the constants and set $c = mathrme^c$ (where the $c$ on the left is different from the $c$ on the right).
– Xander Henderson
Jul 18 at 0:48
If you are worried about keeping track of the constants, perhaps write $$mathrme^x + C_1 = mathrme^C_1 mathrme^x = C_2 mathrme^x, $$ where both $C_1$ and $C_2$ are constant, subject to the relation $C_2 := mathrme^C_1$.
– Xander Henderson
Jul 18 at 0:49
@XanderHenderson Yes, I'm trying to solve a differential equation $fracdydx=y$. By the way, can you helped me to understand in which situation that we can't relabel $c=e^c$. Thanks for your comment, I've edited my question.
– reckn
Jul 18 at 20:30
 |Â
show 1 more comment
1
Note that if $C=e^c$ then $e^x+c=e^ccdot e^x=C e^x$.
– Math Lover
Jul 17 at 21:07
1
$e^x+c = e^ce^x$. Now define $C:=e^c$.
– amsmath
Jul 17 at 21:08
1
It would be really helpful if you could provide some additional context. My guess is that this is popping up in an elementary calculus or differential equations class, where the solution to some DE is of the form $mathrme^x+c$, where $c$ is some constant of integration, which ultimately depends on some initial condition. As others have pointed out, $mathrme^c$ is then also a constant depending on the initial condition, so it does no harm to relabel the constants and set $c = mathrme^c$ (where the $c$ on the left is different from the $c$ on the right).
– Xander Henderson
Jul 18 at 0:48
If you are worried about keeping track of the constants, perhaps write $$mathrme^x + C_1 = mathrme^C_1 mathrme^x = C_2 mathrme^x, $$ where both $C_1$ and $C_2$ are constant, subject to the relation $C_2 := mathrme^C_1$.
– Xander Henderson
Jul 18 at 0:49
@XanderHenderson Yes, I'm trying to solve a differential equation $fracdydx=y$. By the way, can you helped me to understand in which situation that we can't relabel $c=e^c$. Thanks for your comment, I've edited my question.
– reckn
Jul 18 at 20:30
1
1
Note that if $C=e^c$ then $e^x+c=e^ccdot e^x=C e^x$.
– Math Lover
Jul 17 at 21:07
Note that if $C=e^c$ then $e^x+c=e^ccdot e^x=C e^x$.
– Math Lover
Jul 17 at 21:07
1
1
$e^x+c = e^ce^x$. Now define $C:=e^c$.
– amsmath
Jul 17 at 21:08
$e^x+c = e^ce^x$. Now define $C:=e^c$.
– amsmath
Jul 17 at 21:08
1
1
It would be really helpful if you could provide some additional context. My guess is that this is popping up in an elementary calculus or differential equations class, where the solution to some DE is of the form $mathrme^x+c$, where $c$ is some constant of integration, which ultimately depends on some initial condition. As others have pointed out, $mathrme^c$ is then also a constant depending on the initial condition, so it does no harm to relabel the constants and set $c = mathrme^c$ (where the $c$ on the left is different from the $c$ on the right).
– Xander Henderson
Jul 18 at 0:48
It would be really helpful if you could provide some additional context. My guess is that this is popping up in an elementary calculus or differential equations class, where the solution to some DE is of the form $mathrme^x+c$, where $c$ is some constant of integration, which ultimately depends on some initial condition. As others have pointed out, $mathrme^c$ is then also a constant depending on the initial condition, so it does no harm to relabel the constants and set $c = mathrme^c$ (where the $c$ on the left is different from the $c$ on the right).
– Xander Henderson
Jul 18 at 0:48
If you are worried about keeping track of the constants, perhaps write $$mathrme^x + C_1 = mathrme^C_1 mathrme^x = C_2 mathrme^x, $$ where both $C_1$ and $C_2$ are constant, subject to the relation $C_2 := mathrme^C_1$.
– Xander Henderson
Jul 18 at 0:49
If you are worried about keeping track of the constants, perhaps write $$mathrme^x + C_1 = mathrme^C_1 mathrme^x = C_2 mathrme^x, $$ where both $C_1$ and $C_2$ are constant, subject to the relation $C_2 := mathrme^C_1$.
– Xander Henderson
Jul 18 at 0:49
@XanderHenderson Yes, I'm trying to solve a differential equation $fracdydx=y$. By the way, can you helped me to understand in which situation that we can't relabel $c=e^c$. Thanks for your comment, I've edited my question.
– reckn
Jul 18 at 20:30
@XanderHenderson Yes, I'm trying to solve a differential equation $fracdydx=y$. By the way, can you helped me to understand in which situation that we can't relabel $c=e^c$. Thanks for your comment, I've edited my question.
– reckn
Jul 18 at 20:30
 |Â
show 1 more comment
2 Answers
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1
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It truly is :
$$e^x+c = e^c cdot e^x$$
Now, if you simply manipulate the constant $c$ to be $c := e^c$ the expression becomes the desired :
$$boxede^x+c = ce^x$$
add a comment |Â
up vote
0
down vote
Hint
If $c$ is a constant then $e^c$ is still a constant.
Note that in mathematics constant are arbitrary: if a call $c$ a constant and then take $c+1$ I can still call it $c$ (note that this doesn't mean that they are the same constant, but nontheless both of them are a constant)
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
It truly is :
$$e^x+c = e^c cdot e^x$$
Now, if you simply manipulate the constant $c$ to be $c := e^c$ the expression becomes the desired :
$$boxede^x+c = ce^x$$
add a comment |Â
up vote
1
down vote
It truly is :
$$e^x+c = e^c cdot e^x$$
Now, if you simply manipulate the constant $c$ to be $c := e^c$ the expression becomes the desired :
$$boxede^x+c = ce^x$$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
It truly is :
$$e^x+c = e^c cdot e^x$$
Now, if you simply manipulate the constant $c$ to be $c := e^c$ the expression becomes the desired :
$$boxede^x+c = ce^x$$
It truly is :
$$e^x+c = e^c cdot e^x$$
Now, if you simply manipulate the constant $c$ to be $c := e^c$ the expression becomes the desired :
$$boxede^x+c = ce^x$$
answered Jul 17 at 21:07
Rebellos
10k21039
10k21039
add a comment |Â
add a comment |Â
up vote
0
down vote
Hint
If $c$ is a constant then $e^c$ is still a constant.
Note that in mathematics constant are arbitrary: if a call $c$ a constant and then take $c+1$ I can still call it $c$ (note that this doesn't mean that they are the same constant, but nontheless both of them are a constant)
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
add a comment |Â
up vote
0
down vote
Hint
If $c$ is a constant then $e^c$ is still a constant.
Note that in mathematics constant are arbitrary: if a call $c$ a constant and then take $c+1$ I can still call it $c$ (note that this doesn't mean that they are the same constant, but nontheless both of them are a constant)
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Hint
If $c$ is a constant then $e^c$ is still a constant.
Note that in mathematics constant are arbitrary: if a call $c$ a constant and then take $c+1$ I can still call it $c$ (note that this doesn't mean that they are the same constant, but nontheless both of them are a constant)
Hint
If $c$ is a constant then $e^c$ is still a constant.
Note that in mathematics constant are arbitrary: if a call $c$ a constant and then take $c+1$ I can still call it $c$ (note that this doesn't mean that they are the same constant, but nontheless both of them are a constant)
answered Jul 17 at 21:09
Davide Morgante
1,875220
1,875220
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
add a comment |Â
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
Does it mean constant function such $e^c, (c + 11), 3c, sqrtc$, etc is also a constant?
– reckn
Jul 17 at 21:35
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
@Inrtia Yes they are! At the end of the day if $c$ is a number, you can do anything you want whit it and it will remain a number no matter what
– Davide Morgante
Jul 17 at 21:36
add a comment |Â
1
Note that if $C=e^c$ then $e^x+c=e^ccdot e^x=C e^x$.
– Math Lover
Jul 17 at 21:07
1
$e^x+c = e^ce^x$. Now define $C:=e^c$.
– amsmath
Jul 17 at 21:08
1
It would be really helpful if you could provide some additional context. My guess is that this is popping up in an elementary calculus or differential equations class, where the solution to some DE is of the form $mathrme^x+c$, where $c$ is some constant of integration, which ultimately depends on some initial condition. As others have pointed out, $mathrme^c$ is then also a constant depending on the initial condition, so it does no harm to relabel the constants and set $c = mathrme^c$ (where the $c$ on the left is different from the $c$ on the right).
– Xander Henderson
Jul 18 at 0:48
If you are worried about keeping track of the constants, perhaps write $$mathrme^x + C_1 = mathrme^C_1 mathrme^x = C_2 mathrme^x, $$ where both $C_1$ and $C_2$ are constant, subject to the relation $C_2 := mathrme^C_1$.
– Xander Henderson
Jul 18 at 0:49
@XanderHenderson Yes, I'm trying to solve a differential equation $fracdydx=y$. By the way, can you helped me to understand in which situation that we can't relabel $c=e^c$. Thanks for your comment, I've edited my question.
– reckn
Jul 18 at 20:30