Physical meaning of PDE

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When studying PDE, I want to ask if any physical meaning for the following PDE:
$$fracpartial Wpartial u=fracpartial^2 Wpartial x^2$$ such that $t>0, 0<x<infty$ and $W(0,x)=delta_0(x)$. Standard book has physical meaning if $-infty<x<infty$ (Placing a unit impulse at $x=0$ and let it diffuse and recording the temperature). In the example given, can we use the same interpretation? What makes me confuse is that the domain defined. Usually, we do not define at $x=0$ and $t=0$ when I read the books. So I guess $W(u,x)=0$ since $delta_0(x)=0$ if $xneq 0$. But I can think of $W(u,x)neq 0$. $frac1sqrt4pi ue^-fracx^24u$ is a solution







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  • In your equation, should it be $partial W/partial t$ instead of $partial W/partial u$? Also, you need to specify boundary conditions at $x=0$.
    – Rahul
    Jul 18 at 6:50










  • yes, it is $fracpartial Wpartial t$. No, I do not want to specify boundary condition.
    – will_cheuk
    Jul 18 at 7:05










  • What are the boundary conditions at $x=0$ then? A physical interpretation would depend on what these are.
    – Winther
    Jul 22 at 19:03















up vote
2
down vote

favorite












When studying PDE, I want to ask if any physical meaning for the following PDE:
$$fracpartial Wpartial u=fracpartial^2 Wpartial x^2$$ such that $t>0, 0<x<infty$ and $W(0,x)=delta_0(x)$. Standard book has physical meaning if $-infty<x<infty$ (Placing a unit impulse at $x=0$ and let it diffuse and recording the temperature). In the example given, can we use the same interpretation? What makes me confuse is that the domain defined. Usually, we do not define at $x=0$ and $t=0$ when I read the books. So I guess $W(u,x)=0$ since $delta_0(x)=0$ if $xneq 0$. But I can think of $W(u,x)neq 0$. $frac1sqrt4pi ue^-fracx^24u$ is a solution







share|cite|improve this question



















  • In your equation, should it be $partial W/partial t$ instead of $partial W/partial u$? Also, you need to specify boundary conditions at $x=0$.
    – Rahul
    Jul 18 at 6:50










  • yes, it is $fracpartial Wpartial t$. No, I do not want to specify boundary condition.
    – will_cheuk
    Jul 18 at 7:05










  • What are the boundary conditions at $x=0$ then? A physical interpretation would depend on what these are.
    – Winther
    Jul 22 at 19:03













up vote
2
down vote

favorite









up vote
2
down vote

favorite











When studying PDE, I want to ask if any physical meaning for the following PDE:
$$fracpartial Wpartial u=fracpartial^2 Wpartial x^2$$ such that $t>0, 0<x<infty$ and $W(0,x)=delta_0(x)$. Standard book has physical meaning if $-infty<x<infty$ (Placing a unit impulse at $x=0$ and let it diffuse and recording the temperature). In the example given, can we use the same interpretation? What makes me confuse is that the domain defined. Usually, we do not define at $x=0$ and $t=0$ when I read the books. So I guess $W(u,x)=0$ since $delta_0(x)=0$ if $xneq 0$. But I can think of $W(u,x)neq 0$. $frac1sqrt4pi ue^-fracx^24u$ is a solution







share|cite|improve this question











When studying PDE, I want to ask if any physical meaning for the following PDE:
$$fracpartial Wpartial u=fracpartial^2 Wpartial x^2$$ such that $t>0, 0<x<infty$ and $W(0,x)=delta_0(x)$. Standard book has physical meaning if $-infty<x<infty$ (Placing a unit impulse at $x=0$ and let it diffuse and recording the temperature). In the example given, can we use the same interpretation? What makes me confuse is that the domain defined. Usually, we do not define at $x=0$ and $t=0$ when I read the books. So I guess $W(u,x)=0$ since $delta_0(x)=0$ if $xneq 0$. But I can think of $W(u,x)neq 0$. $frac1sqrt4pi ue^-fracx^24u$ is a solution









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asked Jul 18 at 6:38









will_cheuk

1078




1078











  • In your equation, should it be $partial W/partial t$ instead of $partial W/partial u$? Also, you need to specify boundary conditions at $x=0$.
    – Rahul
    Jul 18 at 6:50










  • yes, it is $fracpartial Wpartial t$. No, I do not want to specify boundary condition.
    – will_cheuk
    Jul 18 at 7:05










  • What are the boundary conditions at $x=0$ then? A physical interpretation would depend on what these are.
    – Winther
    Jul 22 at 19:03

















  • In your equation, should it be $partial W/partial t$ instead of $partial W/partial u$? Also, you need to specify boundary conditions at $x=0$.
    – Rahul
    Jul 18 at 6:50










  • yes, it is $fracpartial Wpartial t$. No, I do not want to specify boundary condition.
    – will_cheuk
    Jul 18 at 7:05










  • What are the boundary conditions at $x=0$ then? A physical interpretation would depend on what these are.
    – Winther
    Jul 22 at 19:03
















In your equation, should it be $partial W/partial t$ instead of $partial W/partial u$? Also, you need to specify boundary conditions at $x=0$.
– Rahul
Jul 18 at 6:50




In your equation, should it be $partial W/partial t$ instead of $partial W/partial u$? Also, you need to specify boundary conditions at $x=0$.
– Rahul
Jul 18 at 6:50












yes, it is $fracpartial Wpartial t$. No, I do not want to specify boundary condition.
– will_cheuk
Jul 18 at 7:05




yes, it is $fracpartial Wpartial t$. No, I do not want to specify boundary condition.
– will_cheuk
Jul 18 at 7:05












What are the boundary conditions at $x=0$ then? A physical interpretation would depend on what these are.
– Winther
Jul 22 at 19:03





What are the boundary conditions at $x=0$ then? A physical interpretation would depend on what these are.
– Winther
Jul 22 at 19:03











2 Answers
2






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up vote
0
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This equation describes e.g. heat diffusion.



Your initial condition describes a unit source at $(0, 0)$.



The complex version is e.g. the Schrödinger equation.






share|cite|improve this answer























  • Does it has a solution
    – will_cheuk
    Jul 18 at 7:04










  • This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
    – mvw
    Jul 18 at 7:16










  • Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
    – will_cheuk
    Jul 18 at 7:31

















up vote
0
down vote













The heat-type equation you are studying is the differential formulation (i.e. a formulation involving pointwise values of the quantities involved, like spatial derivatives) of the general balance equation, and the $delta(x)$ represents a source term located in $x=0$ and independent of $t$. To see this, let's analyze the $n$-dimensional case and then particularize the results for $n=1$.



Let $GsubsetmathbbR^n$ a domain for which some form of the divergence theorem holds, for example a Caccioppoli set, and suppose that this set is characterized by a time-dependent quantity $Q(t)$.



The quantity $Q$ can vary respect time only only under the action of sources lying in the interior of $G$ or by flowing across the boundary $partial G$ of $G$: this is the heuristic content of the balance equation
$$
fracmathrmdQ(t)mathrmdt=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdxtag1label1
$$
where



  • $boldsymbolq(x,t)$ is the flux density vector of the quantity $Q(t)$ across $partial G$ at the point $x$

  • $boldsymboln_x$ is the inner (measure theoretic, for a Caccioppoli set) normal at the point $x$.

  • $s(x,t)$ is a general inner term (representing for example processes of absorption/generation of the given quantity taking place within $G$).

The further step in the deduction is to assume a particular form for $Q(t)$ and for the flux $boldsymbolq(x,t)$. This is precisely the meaning of the following equations:
$$
Q(t)=int_G c(x)rho(x) w(x,t),mathrmdx,tag2label2
$$
where



  • $c(x)$ is a function which depends only on the properties of the medium which fills $G$ (if we are dealing with heat, it is called heat capacity),

  • $rho(x)$ is a function which depends only on the density of the medium (it is commonly called mass density),

and
$$
boldsymbolq(x,t)=boldsymbolhatK(x)nabla w(x,t),tag3label3
$$
where $boldsymbolhatK(x)$ is tensor that again takes care of the possibly anisotropic behavior of the flux.



Now, by using equations eqref1, eqref2, eqref3 and the Gauss-Green-Ostrogradsky (divergence) theorem we obtain
$$
beginsplit
fracmathrmdQ(t)mathrmdt &=int_G c(x)rho(x)fracpartial w(x,t)partial t,mathrmdx\
&=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
&=int_partial GboldsymbolhatK(x)nabla w(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
&=int_Gbig[nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)+ s(x,t)big]mathrmdx
endsplit
$$
and then
$$
int_Gleft[ c(x)rho(x)fracpartial w(x,t)partial t-nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)-s(x,t)right]mathrmdx=0
$$
The above equation integral equation is satisfied if and only if
$$
c(x)rho(x)fracpartial w(x,t)partial t=nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big) + s(x,t)tag4label4
$$
Equation eqref4 is the general linear (divergence form) parabolic equation: if we assume $c(x)equivrho(x)equiv1$, $boldsymbolhatK(x)equivboldsymbol1$ and $s(x,t)=delta(x)timesdelta(t)=delta(x)delta(t)$ (the tensor products of Dirac deltas respect to the variables $xinmathbbR^n$ and $tinmathbbR$) we obtain the standard heat equation:
$$
beginsplit
fracpartial w(x,t)partial t&=Delta w(x,t)+delta(x)delta(t)quad n>1\
fracpartial w(x,t)partial t&=fracpartial^2w(x,t)partial x^2+delta(x)delta(t)quad n=1
endsplit
$$
If you need to specify only the presence of a time independent term, basically considering only $delta(x)$ or, the other way out, only a time-dependent term, you can put
$$
s(x,t)=
begincases
delta(x) & xinmathbbR^n\
delta(t) & tinmathbbR
endcases
$$
therefore deltas respect to single variables or their tensor products can be interpreted as source terms in the balance equation eqref1.



Notes



  • Many (if not all) evolution equations of mathematical physics can be deduced from the general balance equation eqref1 (for example the wave equation), just by properly choosing the defining equations eqref2 and eqref3, which therefore play the rôle of constitutive axioms of a theory. In particular eqref3 is the Fourier-Duhamel law of heat conduction.


  • A deduction of the one-dimensional heat equation (without considering the source term), however conceptually identical to the deduction shown above, is offered by Cannon (1984) (§1.1, pp. 13-15) and by Widder (1978) (§2 and §3, pp. 1-5). I prefer the one above since it don't requires the knowledge of any special (however elementary) physical concepts, being valid also for the general linear diffusion equations and other parabolic PDEs.


[1] Cannon, J. R. (1984), The One-Dimensional Heat Equation, Encyclopedia of Mathematics and Its Applications, 23 (1st ed.), Reading etc.: Addison-Wesley Publishing Company, pp. XXV+483, ISBN 978-0-521-30243-2, MR 0747979, Zbl 0567.35001



[2] Widder, D. V. (1978), The Heat Equation, Pure and Applied Mathematics 67, Academic Press, pp. xiv+267, ISBN 0-12-748540-6, MR0466967, Zbl 0322.35041.






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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    This equation describes e.g. heat diffusion.



    Your initial condition describes a unit source at $(0, 0)$.



    The complex version is e.g. the Schrödinger equation.






    share|cite|improve this answer























    • Does it has a solution
      – will_cheuk
      Jul 18 at 7:04










    • This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
      – mvw
      Jul 18 at 7:16










    • Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
      – will_cheuk
      Jul 18 at 7:31














    up vote
    0
    down vote













    This equation describes e.g. heat diffusion.



    Your initial condition describes a unit source at $(0, 0)$.



    The complex version is e.g. the Schrödinger equation.






    share|cite|improve this answer























    • Does it has a solution
      – will_cheuk
      Jul 18 at 7:04










    • This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
      – mvw
      Jul 18 at 7:16










    • Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
      – will_cheuk
      Jul 18 at 7:31












    up vote
    0
    down vote










    up vote
    0
    down vote









    This equation describes e.g. heat diffusion.



    Your initial condition describes a unit source at $(0, 0)$.



    The complex version is e.g. the Schrödinger equation.






    share|cite|improve this answer















    This equation describes e.g. heat diffusion.



    Your initial condition describes a unit source at $(0, 0)$.



    The complex version is e.g. the Schrödinger equation.







    share|cite|improve this answer















    share|cite|improve this answer



    share|cite|improve this answer








    edited Jul 18 at 7:01


























    answered Jul 18 at 6:55









    mvw

    30.5k22250




    30.5k22250











    • Does it has a solution
      – will_cheuk
      Jul 18 at 7:04










    • This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
      – mvw
      Jul 18 at 7:16










    • Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
      – will_cheuk
      Jul 18 at 7:31
















    • Does it has a solution
      – will_cheuk
      Jul 18 at 7:04










    • This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
      – mvw
      Jul 18 at 7:16










    • Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
      – will_cheuk
      Jul 18 at 7:31















    Does it has a solution
    – will_cheuk
    Jul 18 at 7:04




    Does it has a solution
    – will_cheuk
    Jul 18 at 7:04












    This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
    – mvw
    Jul 18 at 7:16




    This article might have it: rose-hulman.edu/~bryan/lottamath/heatkern.pdf
    – mvw
    Jul 18 at 7:16












    Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
    – will_cheuk
    Jul 18 at 7:31




    Thanks. The paper focus on $-infty<x<infty$. I would like to know if we have the same meaning when we consider half plane. Someone requests that the initial function to be a continuous function in $C$ to make further discussions reasonable. (say the boundary $x=0$, we impose a continuous function in $t$ such that initial condition and boundary condition coincide at $t=0,x=0$. I wonder if we can loose this restriction, say at time 0, $W(0,x)=delta_0(x)$ and make heat $W(t,x)=frac1sqrtt$ when $t>0$)
    – will_cheuk
    Jul 18 at 7:31










    up vote
    0
    down vote













    The heat-type equation you are studying is the differential formulation (i.e. a formulation involving pointwise values of the quantities involved, like spatial derivatives) of the general balance equation, and the $delta(x)$ represents a source term located in $x=0$ and independent of $t$. To see this, let's analyze the $n$-dimensional case and then particularize the results for $n=1$.



    Let $GsubsetmathbbR^n$ a domain for which some form of the divergence theorem holds, for example a Caccioppoli set, and suppose that this set is characterized by a time-dependent quantity $Q(t)$.



    The quantity $Q$ can vary respect time only only under the action of sources lying in the interior of $G$ or by flowing across the boundary $partial G$ of $G$: this is the heuristic content of the balance equation
    $$
    fracmathrmdQ(t)mathrmdt=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdxtag1label1
    $$
    where



    • $boldsymbolq(x,t)$ is the flux density vector of the quantity $Q(t)$ across $partial G$ at the point $x$

    • $boldsymboln_x$ is the inner (measure theoretic, for a Caccioppoli set) normal at the point $x$.

    • $s(x,t)$ is a general inner term (representing for example processes of absorption/generation of the given quantity taking place within $G$).

    The further step in the deduction is to assume a particular form for $Q(t)$ and for the flux $boldsymbolq(x,t)$. This is precisely the meaning of the following equations:
    $$
    Q(t)=int_G c(x)rho(x) w(x,t),mathrmdx,tag2label2
    $$
    where



    • $c(x)$ is a function which depends only on the properties of the medium which fills $G$ (if we are dealing with heat, it is called heat capacity),

    • $rho(x)$ is a function which depends only on the density of the medium (it is commonly called mass density),

    and
    $$
    boldsymbolq(x,t)=boldsymbolhatK(x)nabla w(x,t),tag3label3
    $$
    where $boldsymbolhatK(x)$ is tensor that again takes care of the possibly anisotropic behavior of the flux.



    Now, by using equations eqref1, eqref2, eqref3 and the Gauss-Green-Ostrogradsky (divergence) theorem we obtain
    $$
    beginsplit
    fracmathrmdQ(t)mathrmdt &=int_G c(x)rho(x)fracpartial w(x,t)partial t,mathrmdx\
    &=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
    &=int_partial GboldsymbolhatK(x)nabla w(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
    &=int_Gbig[nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)+ s(x,t)big]mathrmdx
    endsplit
    $$
    and then
    $$
    int_Gleft[ c(x)rho(x)fracpartial w(x,t)partial t-nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)-s(x,t)right]mathrmdx=0
    $$
    The above equation integral equation is satisfied if and only if
    $$
    c(x)rho(x)fracpartial w(x,t)partial t=nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big) + s(x,t)tag4label4
    $$
    Equation eqref4 is the general linear (divergence form) parabolic equation: if we assume $c(x)equivrho(x)equiv1$, $boldsymbolhatK(x)equivboldsymbol1$ and $s(x,t)=delta(x)timesdelta(t)=delta(x)delta(t)$ (the tensor products of Dirac deltas respect to the variables $xinmathbbR^n$ and $tinmathbbR$) we obtain the standard heat equation:
    $$
    beginsplit
    fracpartial w(x,t)partial t&=Delta w(x,t)+delta(x)delta(t)quad n>1\
    fracpartial w(x,t)partial t&=fracpartial^2w(x,t)partial x^2+delta(x)delta(t)quad n=1
    endsplit
    $$
    If you need to specify only the presence of a time independent term, basically considering only $delta(x)$ or, the other way out, only a time-dependent term, you can put
    $$
    s(x,t)=
    begincases
    delta(x) & xinmathbbR^n\
    delta(t) & tinmathbbR
    endcases
    $$
    therefore deltas respect to single variables or their tensor products can be interpreted as source terms in the balance equation eqref1.



    Notes



    • Many (if not all) evolution equations of mathematical physics can be deduced from the general balance equation eqref1 (for example the wave equation), just by properly choosing the defining equations eqref2 and eqref3, which therefore play the rôle of constitutive axioms of a theory. In particular eqref3 is the Fourier-Duhamel law of heat conduction.


    • A deduction of the one-dimensional heat equation (without considering the source term), however conceptually identical to the deduction shown above, is offered by Cannon (1984) (§1.1, pp. 13-15) and by Widder (1978) (§2 and §3, pp. 1-5). I prefer the one above since it don't requires the knowledge of any special (however elementary) physical concepts, being valid also for the general linear diffusion equations and other parabolic PDEs.


    [1] Cannon, J. R. (1984), The One-Dimensional Heat Equation, Encyclopedia of Mathematics and Its Applications, 23 (1st ed.), Reading etc.: Addison-Wesley Publishing Company, pp. XXV+483, ISBN 978-0-521-30243-2, MR 0747979, Zbl 0567.35001



    [2] Widder, D. V. (1978), The Heat Equation, Pure and Applied Mathematics 67, Academic Press, pp. xiv+267, ISBN 0-12-748540-6, MR0466967, Zbl 0322.35041.






    share|cite|improve this answer



























      up vote
      0
      down vote













      The heat-type equation you are studying is the differential formulation (i.e. a formulation involving pointwise values of the quantities involved, like spatial derivatives) of the general balance equation, and the $delta(x)$ represents a source term located in $x=0$ and independent of $t$. To see this, let's analyze the $n$-dimensional case and then particularize the results for $n=1$.



      Let $GsubsetmathbbR^n$ a domain for which some form of the divergence theorem holds, for example a Caccioppoli set, and suppose that this set is characterized by a time-dependent quantity $Q(t)$.



      The quantity $Q$ can vary respect time only only under the action of sources lying in the interior of $G$ or by flowing across the boundary $partial G$ of $G$: this is the heuristic content of the balance equation
      $$
      fracmathrmdQ(t)mathrmdt=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdxtag1label1
      $$
      where



      • $boldsymbolq(x,t)$ is the flux density vector of the quantity $Q(t)$ across $partial G$ at the point $x$

      • $boldsymboln_x$ is the inner (measure theoretic, for a Caccioppoli set) normal at the point $x$.

      • $s(x,t)$ is a general inner term (representing for example processes of absorption/generation of the given quantity taking place within $G$).

      The further step in the deduction is to assume a particular form for $Q(t)$ and for the flux $boldsymbolq(x,t)$. This is precisely the meaning of the following equations:
      $$
      Q(t)=int_G c(x)rho(x) w(x,t),mathrmdx,tag2label2
      $$
      where



      • $c(x)$ is a function which depends only on the properties of the medium which fills $G$ (if we are dealing with heat, it is called heat capacity),

      • $rho(x)$ is a function which depends only on the density of the medium (it is commonly called mass density),

      and
      $$
      boldsymbolq(x,t)=boldsymbolhatK(x)nabla w(x,t),tag3label3
      $$
      where $boldsymbolhatK(x)$ is tensor that again takes care of the possibly anisotropic behavior of the flux.



      Now, by using equations eqref1, eqref2, eqref3 and the Gauss-Green-Ostrogradsky (divergence) theorem we obtain
      $$
      beginsplit
      fracmathrmdQ(t)mathrmdt &=int_G c(x)rho(x)fracpartial w(x,t)partial t,mathrmdx\
      &=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
      &=int_partial GboldsymbolhatK(x)nabla w(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
      &=int_Gbig[nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)+ s(x,t)big]mathrmdx
      endsplit
      $$
      and then
      $$
      int_Gleft[ c(x)rho(x)fracpartial w(x,t)partial t-nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)-s(x,t)right]mathrmdx=0
      $$
      The above equation integral equation is satisfied if and only if
      $$
      c(x)rho(x)fracpartial w(x,t)partial t=nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big) + s(x,t)tag4label4
      $$
      Equation eqref4 is the general linear (divergence form) parabolic equation: if we assume $c(x)equivrho(x)equiv1$, $boldsymbolhatK(x)equivboldsymbol1$ and $s(x,t)=delta(x)timesdelta(t)=delta(x)delta(t)$ (the tensor products of Dirac deltas respect to the variables $xinmathbbR^n$ and $tinmathbbR$) we obtain the standard heat equation:
      $$
      beginsplit
      fracpartial w(x,t)partial t&=Delta w(x,t)+delta(x)delta(t)quad n>1\
      fracpartial w(x,t)partial t&=fracpartial^2w(x,t)partial x^2+delta(x)delta(t)quad n=1
      endsplit
      $$
      If you need to specify only the presence of a time independent term, basically considering only $delta(x)$ or, the other way out, only a time-dependent term, you can put
      $$
      s(x,t)=
      begincases
      delta(x) & xinmathbbR^n\
      delta(t) & tinmathbbR
      endcases
      $$
      therefore deltas respect to single variables or their tensor products can be interpreted as source terms in the balance equation eqref1.



      Notes



      • Many (if not all) evolution equations of mathematical physics can be deduced from the general balance equation eqref1 (for example the wave equation), just by properly choosing the defining equations eqref2 and eqref3, which therefore play the rôle of constitutive axioms of a theory. In particular eqref3 is the Fourier-Duhamel law of heat conduction.


      • A deduction of the one-dimensional heat equation (without considering the source term), however conceptually identical to the deduction shown above, is offered by Cannon (1984) (§1.1, pp. 13-15) and by Widder (1978) (§2 and §3, pp. 1-5). I prefer the one above since it don't requires the knowledge of any special (however elementary) physical concepts, being valid also for the general linear diffusion equations and other parabolic PDEs.


      [1] Cannon, J. R. (1984), The One-Dimensional Heat Equation, Encyclopedia of Mathematics and Its Applications, 23 (1st ed.), Reading etc.: Addison-Wesley Publishing Company, pp. XXV+483, ISBN 978-0-521-30243-2, MR 0747979, Zbl 0567.35001



      [2] Widder, D. V. (1978), The Heat Equation, Pure and Applied Mathematics 67, Academic Press, pp. xiv+267, ISBN 0-12-748540-6, MR0466967, Zbl 0322.35041.






      share|cite|improve this answer

























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        down vote










        up vote
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        The heat-type equation you are studying is the differential formulation (i.e. a formulation involving pointwise values of the quantities involved, like spatial derivatives) of the general balance equation, and the $delta(x)$ represents a source term located in $x=0$ and independent of $t$. To see this, let's analyze the $n$-dimensional case and then particularize the results for $n=1$.



        Let $GsubsetmathbbR^n$ a domain for which some form of the divergence theorem holds, for example a Caccioppoli set, and suppose that this set is characterized by a time-dependent quantity $Q(t)$.



        The quantity $Q$ can vary respect time only only under the action of sources lying in the interior of $G$ or by flowing across the boundary $partial G$ of $G$: this is the heuristic content of the balance equation
        $$
        fracmathrmdQ(t)mathrmdt=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdxtag1label1
        $$
        where



        • $boldsymbolq(x,t)$ is the flux density vector of the quantity $Q(t)$ across $partial G$ at the point $x$

        • $boldsymboln_x$ is the inner (measure theoretic, for a Caccioppoli set) normal at the point $x$.

        • $s(x,t)$ is a general inner term (representing for example processes of absorption/generation of the given quantity taking place within $G$).

        The further step in the deduction is to assume a particular form for $Q(t)$ and for the flux $boldsymbolq(x,t)$. This is precisely the meaning of the following equations:
        $$
        Q(t)=int_G c(x)rho(x) w(x,t),mathrmdx,tag2label2
        $$
        where



        • $c(x)$ is a function which depends only on the properties of the medium which fills $G$ (if we are dealing with heat, it is called heat capacity),

        • $rho(x)$ is a function which depends only on the density of the medium (it is commonly called mass density),

        and
        $$
        boldsymbolq(x,t)=boldsymbolhatK(x)nabla w(x,t),tag3label3
        $$
        where $boldsymbolhatK(x)$ is tensor that again takes care of the possibly anisotropic behavior of the flux.



        Now, by using equations eqref1, eqref2, eqref3 and the Gauss-Green-Ostrogradsky (divergence) theorem we obtain
        $$
        beginsplit
        fracmathrmdQ(t)mathrmdt &=int_G c(x)rho(x)fracpartial w(x,t)partial t,mathrmdx\
        &=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
        &=int_partial GboldsymbolhatK(x)nabla w(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
        &=int_Gbig[nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)+ s(x,t)big]mathrmdx
        endsplit
        $$
        and then
        $$
        int_Gleft[ c(x)rho(x)fracpartial w(x,t)partial t-nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)-s(x,t)right]mathrmdx=0
        $$
        The above equation integral equation is satisfied if and only if
        $$
        c(x)rho(x)fracpartial w(x,t)partial t=nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big) + s(x,t)tag4label4
        $$
        Equation eqref4 is the general linear (divergence form) parabolic equation: if we assume $c(x)equivrho(x)equiv1$, $boldsymbolhatK(x)equivboldsymbol1$ and $s(x,t)=delta(x)timesdelta(t)=delta(x)delta(t)$ (the tensor products of Dirac deltas respect to the variables $xinmathbbR^n$ and $tinmathbbR$) we obtain the standard heat equation:
        $$
        beginsplit
        fracpartial w(x,t)partial t&=Delta w(x,t)+delta(x)delta(t)quad n>1\
        fracpartial w(x,t)partial t&=fracpartial^2w(x,t)partial x^2+delta(x)delta(t)quad n=1
        endsplit
        $$
        If you need to specify only the presence of a time independent term, basically considering only $delta(x)$ or, the other way out, only a time-dependent term, you can put
        $$
        s(x,t)=
        begincases
        delta(x) & xinmathbbR^n\
        delta(t) & tinmathbbR
        endcases
        $$
        therefore deltas respect to single variables or their tensor products can be interpreted as source terms in the balance equation eqref1.



        Notes



        • Many (if not all) evolution equations of mathematical physics can be deduced from the general balance equation eqref1 (for example the wave equation), just by properly choosing the defining equations eqref2 and eqref3, which therefore play the rôle of constitutive axioms of a theory. In particular eqref3 is the Fourier-Duhamel law of heat conduction.


        • A deduction of the one-dimensional heat equation (without considering the source term), however conceptually identical to the deduction shown above, is offered by Cannon (1984) (§1.1, pp. 13-15) and by Widder (1978) (§2 and §3, pp. 1-5). I prefer the one above since it don't requires the knowledge of any special (however elementary) physical concepts, being valid also for the general linear diffusion equations and other parabolic PDEs.


        [1] Cannon, J. R. (1984), The One-Dimensional Heat Equation, Encyclopedia of Mathematics and Its Applications, 23 (1st ed.), Reading etc.: Addison-Wesley Publishing Company, pp. XXV+483, ISBN 978-0-521-30243-2, MR 0747979, Zbl 0567.35001



        [2] Widder, D. V. (1978), The Heat Equation, Pure and Applied Mathematics 67, Academic Press, pp. xiv+267, ISBN 0-12-748540-6, MR0466967, Zbl 0322.35041.






        share|cite|improve this answer















        The heat-type equation you are studying is the differential formulation (i.e. a formulation involving pointwise values of the quantities involved, like spatial derivatives) of the general balance equation, and the $delta(x)$ represents a source term located in $x=0$ and independent of $t$. To see this, let's analyze the $n$-dimensional case and then particularize the results for $n=1$.



        Let $GsubsetmathbbR^n$ a domain for which some form of the divergence theorem holds, for example a Caccioppoli set, and suppose that this set is characterized by a time-dependent quantity $Q(t)$.



        The quantity $Q$ can vary respect time only only under the action of sources lying in the interior of $G$ or by flowing across the boundary $partial G$ of $G$: this is the heuristic content of the balance equation
        $$
        fracmathrmdQ(t)mathrmdt=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdxtag1label1
        $$
        where



        • $boldsymbolq(x,t)$ is the flux density vector of the quantity $Q(t)$ across $partial G$ at the point $x$

        • $boldsymboln_x$ is the inner (measure theoretic, for a Caccioppoli set) normal at the point $x$.

        • $s(x,t)$ is a general inner term (representing for example processes of absorption/generation of the given quantity taking place within $G$).

        The further step in the deduction is to assume a particular form for $Q(t)$ and for the flux $boldsymbolq(x,t)$. This is precisely the meaning of the following equations:
        $$
        Q(t)=int_G c(x)rho(x) w(x,t),mathrmdx,tag2label2
        $$
        where



        • $c(x)$ is a function which depends only on the properties of the medium which fills $G$ (if we are dealing with heat, it is called heat capacity),

        • $rho(x)$ is a function which depends only on the density of the medium (it is commonly called mass density),

        and
        $$
        boldsymbolq(x,t)=boldsymbolhatK(x)nabla w(x,t),tag3label3
        $$
        where $boldsymbolhatK(x)$ is tensor that again takes care of the possibly anisotropic behavior of the flux.



        Now, by using equations eqref1, eqref2, eqref3 and the Gauss-Green-Ostrogradsky (divergence) theorem we obtain
        $$
        beginsplit
        fracmathrmdQ(t)mathrmdt &=int_G c(x)rho(x)fracpartial w(x,t)partial t,mathrmdx\
        &=int_partial Gboldsymbolq(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
        &=int_partial GboldsymbolhatK(x)nabla w(x,t)cdotboldsymboln_xmathrmdx+int_G s(x,t),mathrmdx\
        &=int_Gbig[nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)+ s(x,t)big]mathrmdx
        endsplit
        $$
        and then
        $$
        int_Gleft[ c(x)rho(x)fracpartial w(x,t)partial t-nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big)-s(x,t)right]mathrmdx=0
        $$
        The above equation integral equation is satisfied if and only if
        $$
        c(x)rho(x)fracpartial w(x,t)partial t=nablacdotbig(boldsymbolhatK(x)nabla w(x,t)big) + s(x,t)tag4label4
        $$
        Equation eqref4 is the general linear (divergence form) parabolic equation: if we assume $c(x)equivrho(x)equiv1$, $boldsymbolhatK(x)equivboldsymbol1$ and $s(x,t)=delta(x)timesdelta(t)=delta(x)delta(t)$ (the tensor products of Dirac deltas respect to the variables $xinmathbbR^n$ and $tinmathbbR$) we obtain the standard heat equation:
        $$
        beginsplit
        fracpartial w(x,t)partial t&=Delta w(x,t)+delta(x)delta(t)quad n>1\
        fracpartial w(x,t)partial t&=fracpartial^2w(x,t)partial x^2+delta(x)delta(t)quad n=1
        endsplit
        $$
        If you need to specify only the presence of a time independent term, basically considering only $delta(x)$ or, the other way out, only a time-dependent term, you can put
        $$
        s(x,t)=
        begincases
        delta(x) & xinmathbbR^n\
        delta(t) & tinmathbbR
        endcases
        $$
        therefore deltas respect to single variables or their tensor products can be interpreted as source terms in the balance equation eqref1.



        Notes



        • Many (if not all) evolution equations of mathematical physics can be deduced from the general balance equation eqref1 (for example the wave equation), just by properly choosing the defining equations eqref2 and eqref3, which therefore play the rôle of constitutive axioms of a theory. In particular eqref3 is the Fourier-Duhamel law of heat conduction.


        • A deduction of the one-dimensional heat equation (without considering the source term), however conceptually identical to the deduction shown above, is offered by Cannon (1984) (§1.1, pp. 13-15) and by Widder (1978) (§2 and §3, pp. 1-5). I prefer the one above since it don't requires the knowledge of any special (however elementary) physical concepts, being valid also for the general linear diffusion equations and other parabolic PDEs.


        [1] Cannon, J. R. (1984), The One-Dimensional Heat Equation, Encyclopedia of Mathematics and Its Applications, 23 (1st ed.), Reading etc.: Addison-Wesley Publishing Company, pp. XXV+483, ISBN 978-0-521-30243-2, MR 0747979, Zbl 0567.35001



        [2] Widder, D. V. (1978), The Heat Equation, Pure and Applied Mathematics 67, Academic Press, pp. xiv+267, ISBN 0-12-748540-6, MR0466967, Zbl 0322.35041.







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        edited Jul 22 at 16:02


























        answered Jul 22 at 12:34









        Daniele Tampieri

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