Prove for a triangle whose side are in AP

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If the sides of a triangle are in AP and the greatest angle exceeds the smallest angle by a show that the sides are in the ratio 1 - X :1: 1 + X where X = √((1- cos a)(7-cos a))




sequences-and-series triangle arithmetic-progressions




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  • There is a typo, $X$ should be $sqrt (1 - cos a)/(7 - cos a)$.
    – Maxim
    Jul 28 at 20:43










  • Looks related to math.stackexchange.com/questions/2865539/…
    – Henry
    Jul 28 at 23:36














up vote
0
down vote

favorite












If the sides of a triangle are in AP and the greatest angle exceeds the smallest angle by a show that the sides are in the ratio 1 - X :1: 1 + X where X = √((1- cos a)(7-cos a))




sequences-and-series triangle arithmetic-progressions




share|cite|improve this question



















  • There is a typo, $X$ should be $sqrt (1 - cos a)/(7 - cos a)$.
    – Maxim
    Jul 28 at 20:43










  • Looks related to math.stackexchange.com/questions/2865539/…
    – Henry
    Jul 28 at 23:36












up vote
0
down vote

favorite









up vote
0
down vote

favorite











If the sides of a triangle are in AP and the greatest angle exceeds the smallest angle by a show that the sides are in the ratio 1 - X :1: 1 + X where X = √((1- cos a)(7-cos a))




sequences-and-series triangle arithmetic-progressions




share|cite|improve this question











If the sides of a triangle are in AP and the greatest angle exceeds the smallest angle by a show that the sides are in the ratio 1 - X :1: 1 + X where X = √((1- cos a)(7-cos a))





sequences-and-series triangle arithmetic-progressions





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 28 at 19:30









user579305

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  • There is a typo, $X$ should be $sqrt (1 - cos a)/(7 - cos a)$.
    – Maxim
    Jul 28 at 20:43










  • Looks related to math.stackexchange.com/questions/2865539/…
    – Henry
    Jul 28 at 23:36
















  • There is a typo, $X$ should be $sqrt (1 - cos a)/(7 - cos a)$.
    – Maxim
    Jul 28 at 20:43










  • Looks related to math.stackexchange.com/questions/2865539/…
    – Henry
    Jul 28 at 23:36















There is a typo, $X$ should be $sqrt (1 - cos a)/(7 - cos a)$.
– Maxim
Jul 28 at 20:43




There is a typo, $X$ should be $sqrt (1 - cos a)/(7 - cos a)$.
– Maxim
Jul 28 at 20:43












Looks related to math.stackexchange.com/questions/2865539/…
– Henry
Jul 28 at 23:36




Looks related to math.stackexchange.com/questions/2865539/…
– Henry
Jul 28 at 23:36















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