Something confusing in the proof of existence of simple sets in Soarse's book. [closed]

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In Soares's book he tries to prove that there's a simple set and I understand it well but there's something confuses me when he proves that the complement of $A$ is infinite he says that $mathrmcard(textcomplement of $A$ restricted to $2e$)ge e+1$ therefore the complement of $A$ is infinite!!!!!
Or $A$ intersection $[0, 2i) le i$ then the complement of $A$ is infinite!!
I cant figure out why it's infinite???
It's so confusing to me.
Please help if you can.
Thanks!







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closed as off-topic by M. Winter, Xander Henderson, Shailesh, Lord Shark the Unknown, rtybase Jul 26 at 19:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – M. Winter, Xander Henderson, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.












  • What is a simple set?
    – M. Winter
    Jul 24 at 14:03










  • What is $A$ restricted to $2e?$ Please use MathJax to format questions on this site.
    – saulspatz
    Jul 24 at 14:19










  • Think about what happens as $e$ goes to infinity (or as $i$ goes to infinity) ...
    – Noah Schweber
    Jul 25 at 1:48















up vote
2
down vote

favorite












In Soares's book he tries to prove that there's a simple set and I understand it well but there's something confuses me when he proves that the complement of $A$ is infinite he says that $mathrmcard(textcomplement of $A$ restricted to $2e$)ge e+1$ therefore the complement of $A$ is infinite!!!!!
Or $A$ intersection $[0, 2i) le i$ then the complement of $A$ is infinite!!
I cant figure out why it's infinite???
It's so confusing to me.
Please help if you can.
Thanks!







share|cite|improve this question













closed as off-topic by M. Winter, Xander Henderson, Shailesh, Lord Shark the Unknown, rtybase Jul 26 at 19:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – M. Winter, Xander Henderson, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.












  • What is a simple set?
    – M. Winter
    Jul 24 at 14:03










  • What is $A$ restricted to $2e?$ Please use MathJax to format questions on this site.
    – saulspatz
    Jul 24 at 14:19










  • Think about what happens as $e$ goes to infinity (or as $i$ goes to infinity) ...
    – Noah Schweber
    Jul 25 at 1:48













up vote
2
down vote

favorite









up vote
2
down vote

favorite











In Soares's book he tries to prove that there's a simple set and I understand it well but there's something confuses me when he proves that the complement of $A$ is infinite he says that $mathrmcard(textcomplement of $A$ restricted to $2e$)ge e+1$ therefore the complement of $A$ is infinite!!!!!
Or $A$ intersection $[0, 2i) le i$ then the complement of $A$ is infinite!!
I cant figure out why it's infinite???
It's so confusing to me.
Please help if you can.
Thanks!







share|cite|improve this question













In Soares's book he tries to prove that there's a simple set and I understand it well but there's something confuses me when he proves that the complement of $A$ is infinite he says that $mathrmcard(textcomplement of $A$ restricted to $2e$)ge e+1$ therefore the complement of $A$ is infinite!!!!!
Or $A$ intersection $[0, 2i) le i$ then the complement of $A$ is infinite!!
I cant figure out why it's infinite???
It's so confusing to me.
Please help if you can.
Thanks!









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 24 at 14:14
























asked Jul 24 at 14:01









Student

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closed as off-topic by M. Winter, Xander Henderson, Shailesh, Lord Shark the Unknown, rtybase Jul 26 at 19:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – M. Winter, Xander Henderson, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by M. Winter, Xander Henderson, Shailesh, Lord Shark the Unknown, rtybase Jul 26 at 19:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – M. Winter, Xander Henderson, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.











  • What is a simple set?
    – M. Winter
    Jul 24 at 14:03










  • What is $A$ restricted to $2e?$ Please use MathJax to format questions on this site.
    – saulspatz
    Jul 24 at 14:19










  • Think about what happens as $e$ goes to infinity (or as $i$ goes to infinity) ...
    – Noah Schweber
    Jul 25 at 1:48

















  • What is a simple set?
    – M. Winter
    Jul 24 at 14:03










  • What is $A$ restricted to $2e?$ Please use MathJax to format questions on this site.
    – saulspatz
    Jul 24 at 14:19










  • Think about what happens as $e$ goes to infinity (or as $i$ goes to infinity) ...
    – Noah Schweber
    Jul 25 at 1:48
















What is a simple set?
– M. Winter
Jul 24 at 14:03




What is a simple set?
– M. Winter
Jul 24 at 14:03












What is $A$ restricted to $2e?$ Please use MathJax to format questions on this site.
– saulspatz
Jul 24 at 14:19




What is $A$ restricted to $2e?$ Please use MathJax to format questions on this site.
– saulspatz
Jul 24 at 14:19












Think about what happens as $e$ goes to infinity (or as $i$ goes to infinity) ...
– Noah Schweber
Jul 25 at 1:48





Think about what happens as $e$ goes to infinity (or as $i$ goes to infinity) ...
– Noah Schweber
Jul 25 at 1:48











1 Answer
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For every $einBbb N$, a subset of $A^complement$ has cardinality $>e$, so $|A^complement|>e$.






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    For every $einBbb N$, a subset of $A^complement$ has cardinality $>e$, so $|A^complement|>e$.






    share|cite|improve this answer

























      up vote
      0
      down vote













      For every $einBbb N$, a subset of $A^complement$ has cardinality $>e$, so $|A^complement|>e$.






      share|cite|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        For every $einBbb N$, a subset of $A^complement$ has cardinality $>e$, so $|A^complement|>e$.






        share|cite|improve this answer













        For every $einBbb N$, a subset of $A^complement$ has cardinality $>e$, so $|A^complement|>e$.







        share|cite|improve this answer













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        share|cite|improve this answer











        answered Jul 24 at 14:25









        Berci

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        56.4k23570












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