Discrete mathematics / set theory [closed]

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Claim: $A cup A' = U$ (where $U$ is the universal set)



How to prove this using set theory?



Through Venn diagram or through solving?







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closed as off-topic by amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone Aug 4 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.












  • Maybe using definitions ? What is set union ($cup$) ? And what is the complement of a set $A$ (i.e. $A'$) ?
    – Mauro ALLEGRANZA
    Jul 30 at 14:22











  • Venn diagrams are not formal proofs
    – Goldname
    Jul 30 at 14:24










  • Big hint: either a thing exists in this universe or it doesn't.
    – Sean Roberson
    Jul 30 at 14:25














up vote
-6
down vote

favorite












Claim: $A cup A' = U$ (where $U$ is the universal set)



How to prove this using set theory?



Through Venn diagram or through solving?







share|cite|improve this question













closed as off-topic by amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone Aug 4 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.












  • Maybe using definitions ? What is set union ($cup$) ? And what is the complement of a set $A$ (i.e. $A'$) ?
    – Mauro ALLEGRANZA
    Jul 30 at 14:22











  • Venn diagrams are not formal proofs
    – Goldname
    Jul 30 at 14:24










  • Big hint: either a thing exists in this universe or it doesn't.
    – Sean Roberson
    Jul 30 at 14:25












up vote
-6
down vote

favorite









up vote
-6
down vote

favorite











Claim: $A cup A' = U$ (where $U$ is the universal set)



How to prove this using set theory?



Through Venn diagram or through solving?







share|cite|improve this question













Claim: $A cup A' = U$ (where $U$ is the universal set)



How to prove this using set theory?



Through Venn diagram or through solving?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 30 at 15:06









Malkin

915421




915421









asked Jul 30 at 14:20









Kavita Iyer

2




2




closed as off-topic by amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone Aug 4 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone Aug 4 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, Shaun, Jyrki Lahtonen, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.











  • Maybe using definitions ? What is set union ($cup$) ? And what is the complement of a set $A$ (i.e. $A'$) ?
    – Mauro ALLEGRANZA
    Jul 30 at 14:22











  • Venn diagrams are not formal proofs
    – Goldname
    Jul 30 at 14:24










  • Big hint: either a thing exists in this universe or it doesn't.
    – Sean Roberson
    Jul 30 at 14:25
















  • Maybe using definitions ? What is set union ($cup$) ? And what is the complement of a set $A$ (i.e. $A'$) ?
    – Mauro ALLEGRANZA
    Jul 30 at 14:22











  • Venn diagrams are not formal proofs
    – Goldname
    Jul 30 at 14:24










  • Big hint: either a thing exists in this universe or it doesn't.
    – Sean Roberson
    Jul 30 at 14:25















Maybe using definitions ? What is set union ($cup$) ? And what is the complement of a set $A$ (i.e. $A'$) ?
– Mauro ALLEGRANZA
Jul 30 at 14:22





Maybe using definitions ? What is set union ($cup$) ? And what is the complement of a set $A$ (i.e. $A'$) ?
– Mauro ALLEGRANZA
Jul 30 at 14:22













Venn diagrams are not formal proofs
– Goldname
Jul 30 at 14:24




Venn diagrams are not formal proofs
– Goldname
Jul 30 at 14:24












Big hint: either a thing exists in this universe or it doesn't.
– Sean Roberson
Jul 30 at 14:25




Big hint: either a thing exists in this universe or it doesn't.
– Sean Roberson
Jul 30 at 14:25










2 Answers
2






active

oldest

votes

















up vote
1
down vote













Formally, this does it (but is probably overkill):




Take $a in U$.



If $ain A$ then $ A subset (A cup A') implies ain A cup A'$.



If $a notin A$ then, by definition of $A'$, $ a in A'$. Then $A' subset (A cup A') implies ain A cup A'$.



Hence $U subset A cup A'$.



Conversely: since $A subset U$ and $A' subset U$ we immediately have $A cup A'subset U$.



Therefore $U = A cup A'$.




Here's a basic tip when proving that a set $A$ equals another set $B$: if $A subset B$ and $B subset A$ then $A = B$.



First take $a in A$ and prove that $a in B$. This gives you that $A subset B$. Do similar but backwards to show that $B subset A$.






share|cite|improve this answer



















  • 1




    nice formal proof for understanding of set theory without Venn diagram.
    – Ninja hatori
    Jul 30 at 15:51

















up vote
0
down vote













x in U iff x in A or x not in A iff

x in A or x in A' iff x in A $cup$ A'.






share|cite|improve this answer




























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    Formally, this does it (but is probably overkill):




    Take $a in U$.



    If $ain A$ then $ A subset (A cup A') implies ain A cup A'$.



    If $a notin A$ then, by definition of $A'$, $ a in A'$. Then $A' subset (A cup A') implies ain A cup A'$.



    Hence $U subset A cup A'$.



    Conversely: since $A subset U$ and $A' subset U$ we immediately have $A cup A'subset U$.



    Therefore $U = A cup A'$.




    Here's a basic tip when proving that a set $A$ equals another set $B$: if $A subset B$ and $B subset A$ then $A = B$.



    First take $a in A$ and prove that $a in B$. This gives you that $A subset B$. Do similar but backwards to show that $B subset A$.






    share|cite|improve this answer



















    • 1




      nice formal proof for understanding of set theory without Venn diagram.
      – Ninja hatori
      Jul 30 at 15:51














    up vote
    1
    down vote













    Formally, this does it (but is probably overkill):




    Take $a in U$.



    If $ain A$ then $ A subset (A cup A') implies ain A cup A'$.



    If $a notin A$ then, by definition of $A'$, $ a in A'$. Then $A' subset (A cup A') implies ain A cup A'$.



    Hence $U subset A cup A'$.



    Conversely: since $A subset U$ and $A' subset U$ we immediately have $A cup A'subset U$.



    Therefore $U = A cup A'$.




    Here's a basic tip when proving that a set $A$ equals another set $B$: if $A subset B$ and $B subset A$ then $A = B$.



    First take $a in A$ and prove that $a in B$. This gives you that $A subset B$. Do similar but backwards to show that $B subset A$.






    share|cite|improve this answer



















    • 1




      nice formal proof for understanding of set theory without Venn diagram.
      – Ninja hatori
      Jul 30 at 15:51












    up vote
    1
    down vote










    up vote
    1
    down vote









    Formally, this does it (but is probably overkill):




    Take $a in U$.



    If $ain A$ then $ A subset (A cup A') implies ain A cup A'$.



    If $a notin A$ then, by definition of $A'$, $ a in A'$. Then $A' subset (A cup A') implies ain A cup A'$.



    Hence $U subset A cup A'$.



    Conversely: since $A subset U$ and $A' subset U$ we immediately have $A cup A'subset U$.



    Therefore $U = A cup A'$.




    Here's a basic tip when proving that a set $A$ equals another set $B$: if $A subset B$ and $B subset A$ then $A = B$.



    First take $a in A$ and prove that $a in B$. This gives you that $A subset B$. Do similar but backwards to show that $B subset A$.






    share|cite|improve this answer















    Formally, this does it (but is probably overkill):




    Take $a in U$.



    If $ain A$ then $ A subset (A cup A') implies ain A cup A'$.



    If $a notin A$ then, by definition of $A'$, $ a in A'$. Then $A' subset (A cup A') implies ain A cup A'$.



    Hence $U subset A cup A'$.



    Conversely: since $A subset U$ and $A' subset U$ we immediately have $A cup A'subset U$.



    Therefore $U = A cup A'$.




    Here's a basic tip when proving that a set $A$ equals another set $B$: if $A subset B$ and $B subset A$ then $A = B$.



    First take $a in A$ and prove that $a in B$. This gives you that $A subset B$. Do similar but backwards to show that $B subset A$.







    share|cite|improve this answer















    share|cite|improve this answer



    share|cite|improve this answer








    edited Jul 30 at 14:56


























    answered Jul 30 at 14:43









    Malkin

    915421




    915421







    • 1




      nice formal proof for understanding of set theory without Venn diagram.
      – Ninja hatori
      Jul 30 at 15:51












    • 1




      nice formal proof for understanding of set theory without Venn diagram.
      – Ninja hatori
      Jul 30 at 15:51







    1




    1




    nice formal proof for understanding of set theory without Venn diagram.
    – Ninja hatori
    Jul 30 at 15:51




    nice formal proof for understanding of set theory without Venn diagram.
    – Ninja hatori
    Jul 30 at 15:51










    up vote
    0
    down vote













    x in U iff x in A or x not in A iff

    x in A or x in A' iff x in A $cup$ A'.






    share|cite|improve this answer

























      up vote
      0
      down vote













      x in U iff x in A or x not in A iff

      x in A or x in A' iff x in A $cup$ A'.






      share|cite|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        x in U iff x in A or x not in A iff

        x in A or x in A' iff x in A $cup$ A'.






        share|cite|improve this answer













        x in U iff x in A or x not in A iff

        x in A or x in A' iff x in A $cup$ A'.







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 31 at 3:30









        William Elliot

        5,0702414




        5,0702414












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