Mixing
Represent this equation in parametric form [closed]
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Here is my system of linear equations:
$$ x - y + 2z = 1 $$
$$ x + 2y + z = 2 $$
$$ 3x + 5z = 4 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
$$ 3y - z = 1 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
The parameterization part:
Say we let $z = k$
then
$$ y = frac1 + k3 $$
$$ x = 1 + frac1 + k3 + 2k $$
What is the point of parameterization?
linear-algebra
edited Jul 30 at 23:36
David G. Stork
7,3072828
asked Jul 30 at 23:35
Jwan622
1,60811224
closed as unclear what you're asking by B. Mehta, Jyrki Lahtonen, Taroccoesbrocco, Tyrone, Rhys Steele Jul 31 at 10:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
0
down vote
favorite
Here is my system of linear equations:
$$ x - y + 2z = 1 $$
$$ x + 2y + z = 2 $$
$$ 3x + 5z = 4 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
$$ 3y - z = 1 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
The parameterization part:
Say we let $z = k$
then
$$ y = frac1 + k3 $$
$$ x = 1 + frac1 + k3 + 2k $$
What is the point of parameterization?
linear-algebra
edited Jul 30 at 23:36
David G. Stork
7,3072828
asked Jul 30 at 23:35
Jwan622
1,60811224
closed as unclear what you're asking by B. Mehta, Jyrki Lahtonen, Taroccoesbrocco, Tyrone, Rhys Steele Jul 31 at 10:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
What is your question here? Are you asking if your solution is correct or why parametrisation is a useful tool?
– B. Mehta
Jul 30 at 23:39
Both questions. Is it easy to answer both?
– Jwan622
Jul 31 at 1:15
They're very different questions, and as such you should ask them separately. That said, your answer here looks correct (although simplifying the $x$ result is probably sensible).
– B. Mehta
Jul 31 at 1:21
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Here is my system of linear equations:
$$ x - y + 2z = 1 $$
$$ x + 2y + z = 2 $$
$$ 3x + 5z = 4 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
$$ 3y - z = 1 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
The parameterization part:
Say we let $z = k$
then
$$ y = frac1 + k3 $$
$$ x = 1 + frac1 + k3 + 2k $$
What is the point of parameterization?
linear-algebra
edited Jul 30 at 23:36
David G. Stork
7,3072828
asked Jul 30 at 23:35
Jwan622
1,60811224
Here is my system of linear equations:
$$ x - y + 2z = 1 $$
$$ x + 2y + z = 2 $$
$$ 3x + 5z = 4 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
$$ 3y - z = 1 $$
->
$$ x - y + 2z = 1 $$
$$ 3y - z = 1 $$
The parameterization part:
Say we let $z = k$
then
$$ y = frac1 + k3 $$
$$ x = 1 + frac1 + k3 + 2k $$
What is the point of parameterization?
linear-algebra
edited Jul 30 at 23:36
David G. Stork
7,3072828
asked Jul 30 at 23:35
Jwan622
1,60811224
edited Jul 30 at 23:36
David G. Stork
7,3072828
edited Jul 30 at 23:36
David G. Stork
7,3072828
edited Jul 30 at 23:36
David G. Stork
7,3072828
7,3072828
asked Jul 30 at 23:35
Jwan622
1,60811224
asked Jul 30 at 23:35
Jwan622
1,60811224
asked Jul 30 at 23:35
Jwan622
1,60811224
1,60811224
closed as unclear what you're asking by B. Mehta, Jyrki Lahtonen, Taroccoesbrocco, Tyrone, Rhys Steele Jul 31 at 10:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by B. Mehta, Jyrki Lahtonen, Taroccoesbrocco, Tyrone, Rhys Steele Jul 31 at 10:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
What is your question here? Are you asking if your solution is correct or why parametrisation is a useful tool?
– B. Mehta
Jul 30 at 23:39
Both questions. Is it easy to answer both?
– Jwan622
Jul 31 at 1:15
They're very different questions, and as such you should ask them separately. That said, your answer here looks correct (although simplifying the $x$ result is probably sensible).
– B. Mehta
Jul 31 at 1:21
add a comment |Â
2
What is your question here? Are you asking if your solution is correct or why parametrisation is a useful tool?
– B. Mehta
Jul 30 at 23:39
Both questions. Is it easy to answer both?
– Jwan622
Jul 31 at 1:15
They're very different questions, and as such you should ask them separately. That said, your answer here looks correct (although simplifying the $x$ result is probably sensible).
– B. Mehta
Jul 31 at 1:21
2
2
What is your question here? Are you asking if your solution is correct or why parametrisation is a useful tool?
– B. Mehta
Jul 30 at 23:39
What is your question here? Are you asking if your solution is correct or why parametrisation is a useful tool?
– B. Mehta
Jul 30 at 23:39
Both questions. Is it easy to answer both?
– Jwan622
Jul 31 at 1:15
Both questions. Is it easy to answer both?
– Jwan622
Jul 31 at 1:15
They're very different questions, and as such you should ask them separately. That said, your answer here looks correct (although simplifying the $x$ result is probably sensible).
– B. Mehta
Jul 31 at 1:21
They're very different questions, and as such you should ask them separately. That said, your answer here looks correct (although simplifying the $x$ result is probably sensible).
– B. Mehta
Jul 31 at 1:21
add a comment |Â
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2
What is your question here? Are you asking if your solution is correct or why parametrisation is a useful tool?
– B. Mehta
Jul 30 at 23:39
Both questions. Is it easy to answer both?
– Jwan622
Jul 31 at 1:15
They're very different questions, and as such you should ask them separately. That said, your answer here looks correct (although simplifying the $x$ result is probably sensible).
– B. Mehta
Jul 31 at 1:21