tearing off in a random sequence

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I consider the random sequence 0; 1 (0 and 1 are the results of changing coins, heads = 0 and tails = 1) out of 10 random variables. The last three random variables of this random sequence are taken as three separate coin flips. The probability of a combination is 1/8 =0,125?



Example: 0000000111 = 0000000_111



What is the probability of the next combination being 111? 0,125 or 0,125 ^ 2?







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  • As with the earlier version of this question, please pick a notation. Either $0.125$ or $0,125$ but not both. As to the question, if each toss is independent then the probability that you get any specified triple in exactly three tosses is $frac 12^3=frac 18$.
    – lulu
    Jul 30 at 14:39










  • " Either 0.125 or 0,125 but not both." I do not understand what you're talking about
    – vovan
    Jul 30 at 15:38














up vote
-1
down vote

favorite












I consider the random sequence 0; 1 (0 and 1 are the results of changing coins, heads = 0 and tails = 1) out of 10 random variables. The last three random variables of this random sequence are taken as three separate coin flips. The probability of a combination is 1/8 =0,125?



Example: 0000000111 = 0000000_111



What is the probability of the next combination being 111? 0,125 or 0,125 ^ 2?







share|cite|improve this question





















  • As with the earlier version of this question, please pick a notation. Either $0.125$ or $0,125$ but not both. As to the question, if each toss is independent then the probability that you get any specified triple in exactly three tosses is $frac 12^3=frac 18$.
    – lulu
    Jul 30 at 14:39










  • " Either 0.125 or 0,125 but not both." I do not understand what you're talking about
    – vovan
    Jul 30 at 15:38












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I consider the random sequence 0; 1 (0 and 1 are the results of changing coins, heads = 0 and tails = 1) out of 10 random variables. The last three random variables of this random sequence are taken as three separate coin flips. The probability of a combination is 1/8 =0,125?



Example: 0000000111 = 0000000_111



What is the probability of the next combination being 111? 0,125 or 0,125 ^ 2?







share|cite|improve this question













I consider the random sequence 0; 1 (0 and 1 are the results of changing coins, heads = 0 and tails = 1) out of 10 random variables. The last three random variables of this random sequence are taken as three separate coin flips. The probability of a combination is 1/8 =0,125?



Example: 0000000111 = 0000000_111



What is the probability of the next combination being 111? 0,125 or 0,125 ^ 2?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 30 at 15:42
























asked Jul 30 at 14:24









vovan

62




62











  • As with the earlier version of this question, please pick a notation. Either $0.125$ or $0,125$ but not both. As to the question, if each toss is independent then the probability that you get any specified triple in exactly three tosses is $frac 12^3=frac 18$.
    – lulu
    Jul 30 at 14:39










  • " Either 0.125 or 0,125 but not both." I do not understand what you're talking about
    – vovan
    Jul 30 at 15:38
















  • As with the earlier version of this question, please pick a notation. Either $0.125$ or $0,125$ but not both. As to the question, if each toss is independent then the probability that you get any specified triple in exactly three tosses is $frac 12^3=frac 18$.
    – lulu
    Jul 30 at 14:39










  • " Either 0.125 or 0,125 but not both." I do not understand what you're talking about
    – vovan
    Jul 30 at 15:38















As with the earlier version of this question, please pick a notation. Either $0.125$ or $0,125$ but not both. As to the question, if each toss is independent then the probability that you get any specified triple in exactly three tosses is $frac 12^3=frac 18$.
– lulu
Jul 30 at 14:39




As with the earlier version of this question, please pick a notation. Either $0.125$ or $0,125$ but not both. As to the question, if each toss is independent then the probability that you get any specified triple in exactly three tosses is $frac 12^3=frac 18$.
– lulu
Jul 30 at 14:39












" Either 0.125 or 0,125 but not both." I do not understand what you're talking about
– vovan
Jul 30 at 15:38




" Either 0.125 or 0,125 but not both." I do not understand what you're talking about
– vovan
Jul 30 at 15:38















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